What is the next number in this series?
[5031] What is the next number in this series? - Look at the series (11, 23, 58, 132, 134, ?), determine the pattern, and find the value of the next number! - #brainteasers #math #riddles - Correct Answers: 78 - The first user who solved this task is Djordje Timotijevic
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What is the next number in this series?

Look at the series (11, 23, 58, 132, 134, ?), determine the pattern, and find the value of the next number!
Correct answers: 78
The first user who solved this task is Djordje Timotijevic.
#brainteasers #math #riddles
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A young boy enters a barbersho...

A young boy enters a barbershop and the barber whispers to his customer, "This is the dumbest kid in the world. Watch while I prove it to you."
The barber puts a dollar bill in one hand and two quarters in the other, then calls the boy over and asks, "Which do you want, son?"
The boy takes the quarters and leaves.
"What did I tell you?" said the barber. "That kid never learns!"
Later, when the customer leaves, he sees the same young boy coming out of the ice cream store. "Hey, son! May I ask you a question? Why did you take the quarters instead of the dollar bill?"
The boy licked his cone and replied, "Because the day I take the dollar, the game's over!"
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Robert L. Banks

Born 24 Nov 1921; died 3 Jan 1989 at age 67.American chemist who co-discovered crystalline polypropylene polymer, with J. Paul Hogan. They were assigned by Phillips Petroleum, in 1946, to research ways to take the natural gas products propylene and ethylene and turn them into useful gasoline components. On 5 Jun 1951, their experiments using catalysts yielded polypropylene - now used in fibers for rope, indoor-outdoor carpeting and plastics. Banks and Hogan also found how to make a new high-density polyethylene which was more heat resistant than the previously existing polyethylene. Further, their catalysts produced the new polyethylene at only a few hundred psi pressure instead of the existing free radical process which required pressures of up to 30,000 psi.«
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