MAGIC SQUARE: Calculate A-B-C
[8094] MAGIC SQUARE: Calculate A-B-C - The aim is to place the some numbers from the list (11, 12, 17, 20, 21, 23, 26, 33, 41, 42, 47, 48) into the empty squares and squares marked with A, B an C. Sum of each row and column should be equal. All the numbers of the magic square must be different. Find values for A, B, and C. Solution is A-B-C. - #brainteasers #math #magicsquare - Correct Answers: 1
BRAIN TEASERS
enter your answer and press button OK

MAGIC SQUARE: Calculate A-B-C

The aim is to place the some numbers from the list (11, 12, 17, 20, 21, 23, 26, 33, 41, 42, 47, 48) into the empty squares and squares marked with A, B an C. Sum of each row and column should be equal. All the numbers of the magic square must be different. Find values for A, B, and C. Solution is A-B-C.
Correct answers: 1
#brainteasers #math #magicsquare
Register with your Google Account and start collecting points.
Check your ranking on list.

A woman places an ad in the lo...

A woman places an ad in the local newspaper. “Looking for a man with three qualifications: won’t beat me up, won’t run away from me, and is great in bed.” Two days later her doorbell rings. “Hi, I’m Tim. I have no arms so I won’t beat you, and no legs so I won't run away.” “What makes you think you are great in bed?” the woman retorts. Tim replies, “I rang the doorbell, didn’t I?”
Jokes of the day - Daily updated jokes. New jokes every day.
Follow Brain Teasers on social networks

Brain Teasers

puzzles, riddles, mathematical problems, mastermind, cinemania...

Gerd Faltings

Born 28 Jul 1954.German mathematician who wasawardedthe 1986 Fields Medal (the highest honour that a young mathematician can receive) primarily for his proof of the Mordell Conjecture which he achieved using methods of arithmetic algebraic geometry. He has also been closely linked with the work leading to the final proof of Fermat's Last Theorem by Andrew Wiles. In 1983 Faltings proved that for every n > 2 there are at most a finite number of coprime integers x, y, z with xn + yn = zn. This was a major step but a proof that the finite number was 0 in all cases did not seem likely to follow by extending Falting's arguments. However, Faltings was the natural person that Wiles turned to when he wanted an opinion on the correctness of his repair of his proof of Fermat's Last Theorem in 1994.
This site uses cookies to store information on your computer. Some are essential to help the site properly. Others give us insight into how the site is used and help us to optimize the user experience. See our privacy policy.