Math (page 4)These are fun math riddles. All of these tricky riddles are based on real math concepts and can be solved with purely math and logic. These are the tasks listed 31 to 40. |
Find number abc
If a6c5b + cc733 = b355ca find number abc. Multiple solutions may exist.Correct answers: 0
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Calculate the number 373
NUMBERMANIA: Calculate the number 373 using numbers [7, 9, 7, 8, 99, 288] and basic arithmetic operations (+, -, *, /). Each of the numbers can be used only once.Correct answers: 0
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Find number abc
If 704ca + cac1c = 9aa3b find number abc. Multiple solutions may exist.Correct answers: 2
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Calculate the number 2239
NUMBERMANIA: Calculate the number 2239 using numbers [6, 2, 1, 1, 28, 735] and basic arithmetic operations (+, -, *, /). Each of the numbers can be used only once.Correct answers: 0
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MAGIC SQUARE: Calculate A*B*C
The aim is to place the some numbers from the list (3, 4, 11, 19, 20, 27, 42, 43, 50, 90) into the empty squares and squares marked with A, B an C. Sum of each row and column should be equal. All the numbers of the magic square must be different. Find values for A, B, and C. Solution is A*B*C.Correct answers: 0
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Find number abc
If 3bc70 + c7c7b = a9b4b find number abc. Multiple solutions may exist.Correct answers: 0
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Calculate the number 3424
NUMBERMANIA: Calculate the number 3424 using numbers [1, 8, 7, 2, 55, 571] and basic arithmetic operations (+, -, *, /). Each of the numbers can be used only once.Correct answers: 0
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Find number abc
If 514ac - 2baa5 = 24b02 find number abc. Multiple solutions may exist.Correct answers: 1
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Calculate the number 3508
NUMBERMANIA: Calculate the number 3508 using numbers [9, 5, 6, 2, 21, 714] and basic arithmetic operations (+, -, *, /). Each of the numbers can be used only once.Correct answers: 1
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MAGIC SQUARE: Calculate A*B*C
The aim is to place the some numbers from the list (18, 19, 21, 25, 26, 28, 45, 46, 47, 48, 53, 62) into the empty squares and squares marked with A, B an C. Sum of each row and column should be equal. All the numbers of the magic square must be different. Find values for A, B, and C. Solution is A*B*C.Correct answers: 0
#brainteasers #math #magicsquare